48^2+90^2=x^2

Solution for 48^2+90^2=x^2 equation:

48^2+90^2=x^2

We move all terms to the left:

48^2+90^2-(x^2)=0

We add all the numbers together, and all the variables

-1x^2+10404=0

a = -1; b = 0; c = +10404;
Δ = b2-4ac
Δ = 02-4·(-1)·10404
Δ = 41616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{41616}=204$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-204}{2*-1}=\frac{-204}{-2}
=+102
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+204}{2*-1}=\frac{204}{-2}
=-102
$